Rearranging an equation and drawing a blank

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Discussion Overview

The discussion revolves around rearranging the equation (a-b)=(F*b)/(A*E) to solve for the variable b, with a focus on ensuring that the units remain consistent throughout the manipulation. Participants explore the implications of unit cancellation and the correct application of algebraic principles in the context of physics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses difficulty in rearranging the equation to isolate b while maintaining correct units.
  • Another participant requests clarification on the units involved and the specific difficulties encountered.
  • A participant presents a rearranged form of the equation as b=(AEa)/(F+AE) and discusses the units for A, E, a, and F, noting that b should be in mm but is left with N from F.
  • There is a discussion about whether the units for A and E cancel out, with one participant asserting that they do not, leading to confusion about the presence of N in the final expression.
  • A later reply clarifies the unit cancellation process, showing that when dividing by AE, the units simplify correctly to yield mm for b.
  • One participant acknowledges the explanation and expresses that it helped clarify their misunderstanding regarding the cancellation of units.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the initial understanding of unit cancellation, but later contributions clarify the process, leading to a better understanding for at least one participant.

Contextual Notes

The discussion highlights the importance of unit consistency in algebraic manipulation, but does not resolve all uncertainties regarding the initial interpretations of unit cancellation.

samsquaunch
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I need to rearrange this equation to solve for b but I can not get it worked out to where my units end up being correct.

(a-b)=(F*b)/(A*E)
 
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samsquaunch said:
I need to rearrange this equation to solve for b but I can not get it worked out to where my units end up being correct.

(a-b)=(F*b)/(A*E)
Can you retype it with units? Where's your difficulty?
 
I end up with b=(AEa)/(F+AE) but A=mm^2 E=N/mm^2 a=mm F=N and b needs to be mm but I am left with the N from F with nothing to cancel it out.
 
samsquaunch said:
I end up with b=(AEa)/(F+AE) but A=mm^2 E=N/mm^2 a=mm F=N and b needs to be mm but I am left with the N from F with nothing to cancel it out.
##unit(b) = \frac{unit(AEa)}{unit(F+AE)}= \frac{unit(A)unit(E)unit(a)}{unit(F)+unit(A)unit(E)}= \frac{mm^2 \cdot \frac{N}{mm^2} \cdot mm}{N + mm^2 \cdot \frac{N}{mm^2}} = \frac{N \cdot mm}{N} = mm##
 
I don't understand why the N is still on top. Doesn't A and E both cancel each other out so that all that remains is F and a?
 
samsquaunch said:
I don't understand why the N is still on top. Doesn't A and E both cancel each other out so that all that remains is F and a?
What do you mean by "cancel each other out"? ##unit (A\cdot E) = unit(A) \cdot unit (E) = mm^2 \cdot \frac{N}{mm^2} = N##.

If you divide by ##AE## first then you'll have ##b = \frac{a}{\frac{F}{AE} + 1}## and therefore $$unit(b) = \frac{unit(a)}{\frac{unit(F)}{unit(AE)}+unit(1)} = \frac{mm}{\frac{N}{mm^2 \cdot \frac{N}{mm^2}}+0} = \frac{mm}{\frac{N}{N}} = \frac{mm}{1} = mm$$.
 
Alright thank you that just finally made it sink in. I was looking at it if there is an AE on the top and bottom they would just cancel each other out but the way you laid it out here makes a lot of sense.
 

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