- #1
venus_in_furs
- 19
- 1
Hello
I'm working through the see-saw mechanism.
This is currently from the one-generation section.
(I haven't got to the three generation workings yet... although I'm guessing I'll come across something very similar in the three generation model)
Could someone please tell me if it is correct or not that
[itex] \bar{\nu_R} \nu_R^c = \bar{\nu_R^c} \nu_R [/itex]
and if it is, could I please have a hint as to why / how to prove this.
Thank you in advance!
I'm working through the see-saw mechanism.
This is currently from the one-generation section.
(I haven't got to the three generation workings yet... although I'm guessing I'll come across something very similar in the three generation model)
Could someone please tell me if it is correct or not that
[itex] \bar{\nu_R} \nu_R^c = \bar{\nu_R^c} \nu_R [/itex]
and if it is, could I please have a hint as to why / how to prove this.
Thank you in advance!