I know someone posted it before..but i would like to know if given the factor:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] e^{(i/\hbar)S[\phi]} [/tex] (1)

and knowing the progpagator satisfies:

[tex] \Psi (x2,t2)=\int_{-\infty}^{\infty}dxdtK(x2,t2,x1,t1)\Psi(x1,t1) [/tex]

Where S is the action and the propagator is related to (1)

:zzz:

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# Recovering SE from Path integral

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