1. The problem statement, all variables and given/known data A particle has a linearly varying rectilinear acceleration of a=x''i=(12t)i m/s^2. Two observations of the particle's motion are made: Its velocity at t = 1s is x'i=2i m/s, and its position at t= 2s is given bt xi=3i m. (a) Find the displacement of the particle at t=5s relative to where it was at t = 0s. (b) Determine the distance traveled by the particle over the same time interval. 2. Relevant equations 3. The attempt at a solution Given: x''=12t x'(1)=2 x(2)=3 Integrate x''=12t and apply initial conditions and get the equations of motion: x''=12t x'=6t^2-4 x=2t^3-4t-5 (a) plug in: x(5)-x(0) and get 230m. Correct answer (b) Isn't it the same thing? x(5)-x(0)? But the book says its 234 m. No idea how this came about.