Recursive 3D Tiling of Rhombic Dodecahedra

  • Context: Graduate 
  • Thread starter Thread starter Ventrella
  • Start date Start date
  • Tags Tags
    3d
Click For Summary
SUMMARY

The discussion centers on the recursive tiling of rhombic dodecahedra, which can indefinitely tile space due to their unique geometric properties. A single rhombic dodecahedron can be surrounded by 12 others, creating a complete volume of 13 without gaps. The inquiry explores whether this tiling can be repeated with the resulting shapes, potentially leading to a fractal boundary. However, a counterargument suggests that this recursive process may not be feasible due to the creation of hollows in the arrangement.

PREREQUISITES
  • Understanding of polyhedral geometry, specifically rhombic dodecahedra
  • Knowledge of sphere packing principles
  • Familiarity with fractal geometry concepts
  • Basic modeling skills for geometric constructions
NEXT STEPS
  • Research the properties of rhombic dodecahedra and their tiling capabilities
  • Explore sphere packing theories and their implications in geometry
  • Study fractal geometry and its relationship with polyhedral structures
  • Experiment with 3D modeling software to visualize recursive tiling
USEFUL FOR

Mathematicians, geometricians, and 3D modelers interested in advanced polyhedral structures and their applications in fractal geometry.

Ventrella
Messages
28
Reaction score
4
I have a question about rhombic dodecahedra - polyhedra which can be tiled indefinitely, and which correspond to the closest packing of spheres. A single rhombic dodecahedron can be surrounded by 12 rhombic dodecahedra, making a tiling of 13 (having no gaps or holes or cracks). This creates a new volume which can be described as the union of 13 rhombic dodecahedra.

My question is this: Can I then take 13 of these shapes and tile them in the same fashion, as if they were each rhombic dodecahedra? And can this process be repeated indefinitely? If so, the boundary would approximate a fractal surface. I have an intuition that this would be true, but I'm not sure how to verify this (other than building models and coming up with a conjecture).

Thanks!
-j
 
Physics news on Phys.org
I don't think you can. They leave 14 hollows, yes? Do the same with 13 balls; they do not stack to a ball.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 35 ·
2
Replies
35
Views
11K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K