Redox Reactions Homework: Cr+2, K2Cr2O7, HNO3 Answers

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SUMMARY

The discussion centers on redox reactions involving chromium species, specifically Cr2+ and K2Cr2O7 in the presence of HNO3. The reduction half-reaction for Cr2+ is correctly identified as Cr2+ + 2e- → Cr(s). The participants conclude that the reaction between acidified K2Cr2O7 and HNO3 will not occur, as both substances are already oxidized and cannot be further oxidized without additional reagents.

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  • Understanding of redox reactions and half-reactions
  • Familiarity with chromium species, specifically Cr2+ and Cr2O72-
  • Knowledge of acid-base chemistry, particularly involving nitric acid (HNO3)
  • Ability to interpret electrochemical series tables
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  • Research the electrochemical series and its applications in predicting redox reactions
  • Study the properties and reactions of K2Cr2O7 in acidic solutions
  • Learn about the oxidation states of chromium and their implications in redox chemistry
  • Explore advanced redox reactions involving exotic oxidizing agents
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Chemistry students, educators, and professionals involved in redox chemistry, particularly those studying transition metals and their reactions in acidic environments.

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Homework Statement


1) Give the resultant fomula for: Cr2+ gets reduced.

2) Will the following reaction occur? Acidified K2Cr2O7 solution is added to HNO3(nitric acid).


Homework Equations


N/A


The Attempt at a Solution


1) I put: Cr+2 + 2e- ---> Cr(s); I have one question though...doesn't this half-reaction not exist?

2) I put no for this question because I saw that all 4 species are oxidizers. But I am just wondering, if it says acidified K2Cr2O7, does that just refer to: the reaction with Cr2O7-2 that includes 14H+?
 
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The answer to the first question is correct. For the second question you should consult a table of the electrochemical series. You might find this in an Appendix of your textbook or you can consult the CRC Handbook of Chemistry and Physics.
 
In general chemisttree is right that you should consult tables. However, you mix two substances that are already oxidized. Neither HNO3 nor K2Cr2O7 can be further oxidized as long as we are not talking about some exotic compounds (to be honest - I am not aware of such compounds, but then I know I don't know everything :) ).
 

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