Redox reactions oxidation number method

[Coco12]

1) Problem Statement

2) Relevant Equations3) Attempt at Solution
For question d, I realize in this case that the substance that is oxidized and reduced is the same molecule : iodine.
How do I proceed then as the next step would ask for you to find the change in oxidation numbers and multiplying by coefficients?
You would have 2 different changes number ( 7 and 1)?

 

[Borek]

You would have 2 different changes number ( 7 and 1)?

Yes.

 

[Coco12]

Yes.

Where do you go from there?

 

[Borek]

Same thing you do with other reactions - one half reaction is for reduction, other is for oxidation, just combine them.

 

[Coco12]

Same thing you do with other reactions - one half reaction is for reduction, other is for oxidation, just combine them.

So it would be 7/2 * 1/2 to give you 7/4 , then you multiply everything by 4?

 

[Borek]

I am not going to try to guess what you mean, if you want us to help it is up to you to explain what is what of what.

 

[Coco12]

I am not going to try to guess what you mean, if you want us to help it is up to you to explain what is what of what.

Thank you. I understand now.