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Redox reactions oxidation number method

  1. Jan 8, 2014 #1
    1) Problem Statement
    ImageUploadedByPhysics Forums1389217019.130425.jpg


    2) Relevant Equations


    3) Attempt at Solution
    For question d, I realize in this case that the substance that is oxidized and reduced is the same molecule : iodine.
    How do I proceed then as the next step would ask for you to find the change in oxidation numbers and multiplying by coefficients?
    You would have 2 different changes number ( 7 and 1)?
     
  2. jcsd
  3. Jan 8, 2014 #2

    Borek

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    Staff: Mentor

    Yes.
     
  4. Jan 8, 2014 #3

    Where do you go from there?
     
    Last edited: Jan 9, 2014
  5. Jan 9, 2014 #4

    Borek

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    Staff: Mentor

    Same thing you do with other reactions - one half reaction is for reduction, other is for oxidation, just combine them.
     
  6. Jan 9, 2014 #5
    So it would be 7/2 * 1/2 to give you 7/4 , then you multiply everything by 4?
     
  7. Jan 9, 2014 #6

    Borek

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    Staff: Mentor

    I am not going to try to guess what you mean, if you want us to help it is up to you to explain what is what of what.
     
  8. Jan 10, 2014 #7

    Thank you. I understand now.
     
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