Reducing Boolean Expressions: Axioms and Simplification Techniques

  • Context: Undergrad 
  • Thread starter Thread starter deathprog23
  • Start date Start date
  • Tags Tags
    Expression Reduction
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 4K views
deathprog23
Messages
5
Reaction score
0
I have been stumped by a simplification problem - well, I can solve it, but I'm not sure how to do it axiomatically!

The expression is A(B+C)+B'D+C'D'

I can see that the (B+C) is redundant in the first term - if A is true, the whole is true regardless of (B+C)'s value. So it reduces to A+B'D+C'D'

What axioms are used in the proof of this? Thanks!
 
Physics news on Phys.org
tiny-tim said:
Hi deathprog23! :smile:

Hint: you need to prove that B'C' lies in B'D+C'D' :wink:

Nice hint! I got it now, thanks very much :)