Reduction Gearbox Calculation question

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The discussion centers on calculating the torque required to turn the output shaft of a 500:1 reduction gearbox when applying force in reverse. It is clarified that simply multiplying the input shaft torque by 500 is not accurate due to the high gear ratio. The presence of friction from bearings and gear teeth significantly complicates the calculation, as these factors increase at each stage of the gearbox. Therefore, a more detailed analysis considering these frictional losses is necessary for an accurate torque estimation. Understanding these dynamics is crucial for effective gearbox performance evaluation.
UrSleyeNess
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If Have have the torque needed to turn the input shaft of a 500:1 Gearbox with no load, can that information allow me to calculate the opposite. I want to know the torque required to turn the output shaft.

What I mean is, if you were to apply the force to the output shaft. In other words, use a Reduction gearbox in reverse.

This has been driving me nut to figure out if it is as simple as taking the torque required to turn the input shaft and multiply it by 500 since I am talking a 500:1 ratio...

Reply here if you know or email me directly at <email address deleted by Moderator>

Thanks
Chris
 
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UrSleyeNess said:
This has been driving me nut to figure out if it is as simple as taking the torque required to turn the input shaft and multiply it by 500 since I am talking a 500:1 ratio...

No - not for a ratio as high as 500:1 .
 
Nidum said:
No - not for a ratio as high as 500:1 .

If not then why and how would I calculate it?
 
The difficulty is that the friction loading due to any bearing friction and any contact friction between the gear teeth is going to be multiplied at each stage as well.
 

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