Why Na & K are Not Acceptable for Reducing PbCl2

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SUMMARY

The discussion centers on the reduction of lead(II) chloride (PbCl2) and why sodium (Na) and potassium (K) are not suitable reducing agents. The acceptable reducing agents identified are iron (Fe) and magnesium (Mg), which can effectively displace lead ions in a single displacement reaction. The primary reasons for the exclusion of Na and K include their cost and the fact that NaCl2 and KCl2 are not valid chemical formulas, unlike FeCl2 and MgCl2. Thus, while all mentioned metals can theoretically displace Pb2+, practical and chemical validity factors limit the use of Na and K.

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Homework Statement


A question asked to write an equation for the reduction of PbCl2

The answer key was
PbCl2+X ----> Pb+XCl2
where X can be: ...Fe, Mg...but not Na or K

Why are Na or K not acceptable?
 
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Cost could be one reason. And which would you rather work with: sodium / potassium vs. iron / magnesium?
 
Based on the activity series, all of those metals should be able to displace Pb2+ in a single displacement reaction. Maybe it just has to do with the fact that FeCl2 and MgCl2 are valid formula but NaCl2 and KCl2 are not (rather the equation would be PbCl2 + 2Na --> Pb + 2NaCl).
 
Ygggdrasil said:
Based on the activity series, all of those metals should be able to displace Pb2+ in a single displacement reaction. Maybe it just has to do with the fact that FeCl2 and MgCl2 are valid formula but NaCl2 and KCl2 are not (rather the equation would be PbCl2 + 2Na --> Pb + 2NaCl).

The question doesn't make any such type of recommendation though
 

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