Reflection coefficient for light at air-silver interface at optical frequency

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drcrabs
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How does one calculate the reflection coefficient for light at an air to silver interface at optical frequencies ([tex]\omega = {4 *10^{15} s^{-1}}[/tex])
given

[tex]\mu_{I} = \mu_{T} = \mu_{0} , \sigma = {6 * 10^7 mhom^{-1}}[/tex]
 
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The reflection is close to 100% for silver.
the reflected intensity is I_r=I_0-I_absorbed.
[itex]I_{absorbed}=\sqrt{\omega/8\pi\sigma}I_0[/itex] in Gaussian units.
 
Would this work?

Knowing the frequency means we can find the wavelength clearly, which has units metres, clearly. When combined with [tex]\sigma = {6 * 10^7 mhom^{-1}}[/tex] to get the impedance of the silver. Then taking the ratio with the impedance of free space and assuming normal incidence

[tex]r =\frac{1 - \beta}{1 + \beta}[/tex]

where [tex]\beta = \frac{\eta_0}{\eta_s}[/tex]

Would this work?
 
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How would you calculate \eta?
 
eta_s is the impeance of silver. As indicated previously a value with ohm units can be achieved by combining wavelength with the value of conductivity. What I am asking is, is this a valid statement?
 
No. Units are not a calculation.
 
i want to know about the motion of the stelites totely
 
basic defination of electromagnatic physics