BlackHole213
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I know that the bound eigenstates for the reflectionless potential (Poschl-Teller potential) is
[itex]\Psi_{\lambda,\mu}=P^{\lambda}_{\mu}[/itex](tanh(x))
where
[itex]P^{\lambda}_{\mu}[/itex] are the associated Legendre polynomials and [itex]\lambda[/itex] is a positive integer while [itex]\mu[/itex] is an integer able to take on values from [itex]\lambda, \lambda-1, ... , 1[/itex]
Is this the same equation for unbound states. For example, if [itex]\lambda=1.1[/itex], would I be able to use the top equation or is a different equation be necessary?
I'm attempting to compare the eigenstates for [itex]\lambda=1[/itex] to [itex]\lambda=1.1[/itex] as seen on:
http://demonstrations.wolfram.com/EigenstatesForPoeschlTellerPotentials/
Thanks.
[itex]\Psi_{\lambda,\mu}=P^{\lambda}_{\mu}[/itex](tanh(x))
where
[itex]P^{\lambda}_{\mu}[/itex] are the associated Legendre polynomials and [itex]\lambda[/itex] is a positive integer while [itex]\mu[/itex] is an integer able to take on values from [itex]\lambda, \lambda-1, ... , 1[/itex]
Is this the same equation for unbound states. For example, if [itex]\lambda=1.1[/itex], would I be able to use the top equation or is a different equation be necessary?
I'm attempting to compare the eigenstates for [itex]\lambda=1[/itex] to [itex]\lambda=1.1[/itex] as seen on:
http://demonstrations.wolfram.com/EigenstatesForPoeschlTellerPotentials/
Thanks.