Related Rates and a Conical Tank

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SUMMARY

The discussion centers on the dynamics of water flow in an inverted conical tank with a depth of 10 meters and a top radius of 8 meters. Water enters the tank at a rate of 0.1 cubic meters per minute while leaking out at a rate of 0.001h² cubic meters per minute, where h represents the water depth. The volume of water in the tank is expressed as V = (16π/75)h³. The key question is whether the tank can overflow given these rates of inflow and outflow.

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  • Understanding of calculus, specifically related rates.
  • Familiarity with the geometry of conical shapes.
  • Knowledge of volume formulas for three-dimensional shapes.
  • Basic principles of fluid dynamics.
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A water tank is in the shape of an inverted cone with depth 10 meters and top radius 8 meters. Water is flowing into the tank at 0.1 cubic meters/min but leaking out at a rate of 0.001h2 cubic meters/min, where h is the depth of the water in the tank in meters. Can the tank ever overflow?

Can anyone help with this? The flowing in and leaking out is a bit confusing.
 
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V = \frac{1}{3}\pi r^{2} hYou know that \frac{r}{h} = \frac{4}{5}, so r = \frac{4h}{5}

So the new expression is: V = \frac{1}{3}\pi (\frac{4h}{5})^{2}h = \frac{16\pi}{75}h^{3}

You also know that \frac{dV}{dt} = 0.1 - 0.001
 
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