Related rates calculus problem about a water tank

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SUMMARY

The discussion centers on a related rates calculus problem involving a rectangular water tank with a height measurement error of ±1 cm. The tank has a constant base length of 200 cm and features 100 holes, each with the same flow rate. The speed of efflux from the holes is determined by the formula v = √(2gh), where h represents the vertical distance from the water surface to the hole. Consequently, holes positioned closer to the bottom of the tank exhibit higher flow rates compared to those nearer the top.

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  • Understanding of related rates in calculus
  • Familiarity with fluid dynamics principles
  • Knowledge of the efflux speed formula v = √(2gh)
  • Basic skills in differential equations
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  • Explore fluid dynamics concepts, particularly the Bernoulli's principle
  • Learn how to derive and apply the efflux speed formula in various contexts
  • Practice solving differential equations related to flow rates
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jaychay
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Summary:: Consider the rectangular water tank, at the base the length is the same for 200 cm. There are 100 holes for water to come out which each hole have the same flow rate. Find the amount of water that come out in each hole by using differential when we know that there is an error in the measurement of the height of the water in the tank is not exceed ± 1 cm.

Can you please help me or hint me how to do it because I have tried many times to solve it and I still cannot find the answer to the question
Thank you very much in advice !
 

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jaychay said:
There are 100 holes for water to come out which each hole have the same flow rate.

That part doesn't make sense to me; the speed of efflux is given by ##v = \sqrt{2gh}## where ##h## is the vertical distance to from the hole to the surface. If the area of any given hole is ##A##, then the flow rate ##dV/dt## through that particular hole will be ##A\sqrt{2gh}##. It follows the holes nearer the floor will have greater flow rates than the holes nearer the top.
 
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