1. The problem statement, all variables and given/known data the Pth, Qth & Rth terms of an arithmetic sequence are in geometric progression. Show that the common ratio is (q-r)/(p-q) or (p-q)/(q-r). 2. Relevant equations for an A.P, the Nth term= a (n-1)d for a G.P, the Nth term= ar^(n-1) 3. The attempt at a solution let the Pth, Qth & Rth term be p, q & r respectively. Since they are in A.P, "d"= q-p = r-q also, since they form a GP, "r"= (p/q)or(q/p)= (r/q)or(q/r) don't really know if to make the assumption that for this case, "d"= "r", is pretty safe! So please what do i do next? Thanks in anticipation!