Relationship between magnitude of current and magnetic field

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SUMMARY

The discussion centers on the relationship between the magnitude of current and the magnetic force between two current-carrying conductors. It is established that while a conductor with a greater current produces a stronger magnetic field, the force exerted by each conductor on the other is proportional to the current of the second conductor. This relationship is mathematically expressed as the forces being equal and opposite, adhering to Newton's Third Law. The forces are calculated using the magnetic field equations for infinite parallel conductors, demonstrating that the product of the currents determines the force magnitude.

PREREQUISITES
  • Understanding of Newton's Third Law of Motion
  • Familiarity with magnetic fields generated by currents
  • Knowledge of the equations for magnetic force between parallel conductors
  • Basic algebra for manipulating equations involving currents and magnetic fields
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  • Study the derivation of the magnetic force equations for parallel conductors
  • Learn about the Biot-Savart Law and its application in calculating magnetic fields
  • Explore the concept of magnetic field lines and their relation to current direction
  • Investigate applications of magnetic forces in electrical engineering and physics
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Students of physics, electrical engineers, and educators seeking to deepen their understanding of electromagnetic interactions and the principles governing magnetic forces between conductors.

ellieee
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Homework Statement
why is the magnitude of magnetic force acting on both conductors the same even if the currents are not equal? in my opinion, when there is more current, doesn't it mean there is more electricity, so larger magnetic field?
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ellieee said:
Homework Statement:: why is the magnitude of magnetic force acting on both conductors the same even if the currents are not equal? in my opinion, when there is more current, doesn't it mean there is more electricity, so larger magnetic field?
I assume you are talking about the force between two current-carrying conductors.

The conductor with the greater current will produce the greater magnetic field. But the force it exerts on the other conductor is proportional to that second conductor's current. So the force they exert on each other is the same.
 
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
 
Doc Al said:
But the force it exerts on the other conductor is proportional to that second conductor's current
then example if the "magnitude" of the 1st conductor has a bigger magnetic strength of 10 and the 2nd conductor is 5, so in the end they will exert a magnetic force of magnitude 5 on each other ?
 
Delta2 said:
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
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Delta2 said:
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
hmm I don't really get it tho sorry:( can u look at my post 4?
 
Well it is because if we do the math (which you don't understand but ok I can't do much about it) we end up that both forces are proportional to the product of currents ##I_1I_2##, so it doesn't really matter if the currents are not equal. Both currents contribute to the magnitude of both forces.
 
ellieee said:
then example if the "magnitude" of the 1st conductor has a bigger magnetic strength of 10 and the 2nd conductor is 5, so in the end they will exert a magnetic force of magnitude 5 on each other ?
No. (As @Delta2 explained.)

The field from conductor #1 is proportional to ##I_1##; but the force it exerts on conductor #2 is also proportional to the current in #2 (##I_2##). So the force is proportional to ##I_1I_2##.

And if you were to figure out the force on #1 from #2, you'd find it's proportional to ##I_2I_1## -- which is the same as ##I_1I_2##.

And, as @Delta2 points out, this had better be the case to satisfy Newton's 3rd law.

You might want to read this: Magnetic Force Between Wires
 
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