Relationship between magnitude of current and magnetic field

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Homework Help Overview

The discussion revolves around the relationship between the magnitude of current and the magnetic force acting on current-carrying conductors. Participants are exploring the principles of electromagnetism, particularly focusing on the forces between two parallel conductors with different currents.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are questioning why the magnetic force is the same for both conductors despite differing currents. There are attempts to clarify the relationship between current, magnetic field strength, and the resulting forces. Some participants invoke Newton's 3rd Law to support their reasoning.

Discussion Status

The discussion is active, with participants providing mathematical reasoning and attempting to clarify misconceptions. Some guidance has been offered regarding the proportionality of forces to the product of the currents, but there remains some confusion among participants regarding the implications of these relationships.

Contextual Notes

Participants are grappling with the mathematical details and implications of the forces involved, indicating a need for further exploration of the concepts without providing complete solutions.

ellieee
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Homework Statement
why is the magnitude of magnetic force acting on both conductors the same even if the currents are not equal? in my opinion, when there is more current, doesn't it mean there is more electricity, so larger magnetic field?
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ellieee said:
Homework Statement:: why is the magnitude of magnetic force acting on both conductors the same even if the currents are not equal? in my opinion, when there is more current, doesn't it mean there is more electricity, so larger magnetic field?
I assume you are talking about the force between two current-carrying conductors.

The conductor with the greater current will produce the greater magnetic field. But the force it exerts on the other conductor is proportional to that second conductor's current. So the force they exert on each other is the same.
 
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
 
Doc Al said:
But the force it exerts on the other conductor is proportional to that second conductor's current
then example if the "magnitude" of the 1st conductor has a bigger magnetic strength of 10 and the 2nd conductor is 5, so in the end they will exert a magnetic force of magnitude 5 on each other ?
 
Delta2 said:
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
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Delta2 said:
Without going into math details, we can invoke Newton's 3rd Law and get that the two forces are equal and opposite, but anyway:
Well let me do the math for you to see that they are equal:
Suppose we have to infinite parallel conductors with currents ##I_1,I_2##, and the respective magnetic fields ##B_1(r)=\frac{\mu_0}{2\pi}\frac{I_1}{r}##, ##B_2(r)=\frac{\mu_0}{2\pi}\frac{I_2}{r-d}##, where d is their in between distance.

Then the force from 1 to 2 $$F_{12}=B_1(d)I_2L$$ while the force from 2 to 1 is $$F_{21}=B_2(0)I_1L$$. It is elementary math to work out to see that $$F_{12}=-F_{21}$$.
hmm I don't really get it tho sorry:( can u look at my post 4?
 
Well it is because if we do the math (which you don't understand but ok I can't do much about it) we end up that both forces are proportional to the product of currents ##I_1I_2##, so it doesn't really matter if the currents are not equal. Both currents contribute to the magnitude of both forces.
 
ellieee said:
then example if the "magnitude" of the 1st conductor has a bigger magnetic strength of 10 and the 2nd conductor is 5, so in the end they will exert a magnetic force of magnitude 5 on each other ?
No. (As @Delta2 explained.)

The field from conductor #1 is proportional to ##I_1##; but the force it exerts on conductor #2 is also proportional to the current in #2 (##I_2##). So the force is proportional to ##I_1I_2##.

And if you were to figure out the force on #1 from #2, you'd find it's proportional to ##I_2I_1## -- which is the same as ##I_1I_2##.

And, as @Delta2 points out, this had better be the case to satisfy Newton's 3rd law.

You might want to read this: Magnetic Force Between Wires
 
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