Relative motion and displacement

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SUMMARY

The discussion focuses on calculating the resultant displacement of a man walking in various directions: 600m at [E47 degrees N], 500m at [N38 degrees W], 300m at [W29 degrees S], and 400m at [S13 degrees E]. The correct interpretation of the directional notation is clarified, specifically that [E47 degrees N] means measuring 47 degrees counterclockwise from the east axis. This understanding is crucial for accurately determining the resultant displacement using vector addition.

PREREQUISITES
  • Understanding of vector addition in physics
  • Familiarity with trigonometric functions for calculating components
  • Knowledge of directional notation in navigation
  • Ability to use a protractor for angle measurement
NEXT STEPS
  • Study vector addition techniques in physics
  • Learn how to resolve vectors into their components
  • Explore trigonometric functions such as sine and cosine
  • Practice problems involving displacement and direction in navigation
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Students studying physics, particularly those focusing on mechanics and vector analysis, as well as anyone interested in navigation and directional calculations.

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Homework Statement


a man walks 600m [E47 degree N] then 500m [N38 degree W] then 300m [W29degree S] and finnally 400m [S13degree E]


Homework Equations



find this resultant displacement.

The Attempt at a Solution


my problem is .. [E47 degree N] ... does that mean i must put the protractor's 0 degree at East or north ?
 
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[E 47 degrees N] implies the angle is 47 degrees north of east , so, yes, you place the protractor's 0 degree mark at east, then measure up 47 degrees counterclockwise from the positive x (east) axis.
 
PhanthomJay said:
[E 47 degrees N] implies the angle is 47 degrees north of east , so, yes, you place the protractor's 0 degree mark at east, then measure up 47 degrees counterclockwise from the positive x (east) axis.

ok thank you very much .. .. :) :) :)
 

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