Displacement of deflected puck on ice

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Homework Help Overview

The problem involves determining the total displacement of a puck on ice after it travels two segments: the first segment is 20.0 m at an angle of 5.0 degrees east of north, and the second segment is 30.0 m at an angle of 35.0 degrees north of west. The original poster expresses confusion regarding the direction of the second displacement vector.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for a visual representation of the problem, with suggestions to attach diagrams. There is mention of using the law of cosines, but some participants prefer a simpler approach. The original poster is uncertain about how to correctly represent the second displacement vector.

Discussion Status

Participants are actively engaging in clarifying the problem setup and discussing how to visualize the displacements. There is no explicit consensus on the method to solve the problem, but guidance is being offered regarding the drawing of vectors.

Contextual Notes

There is a request for visual aids, indicating that the original poster may be struggling with the geometric interpretation of the problem. The discussion reflects a collaborative effort to clarify the setup without providing direct solutions.

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Homework Statement


a puck on the ice travels 20.0 m [5.0 degrees E of N], gets deflected, and travels 30.0 m [35.0° N of W]. Determine where the puck will end up with respect to its starting point, e.g., the puck's total displacement

Homework Equations


c^2=a^2+b^2-2abcosC

The Attempt at a Solution


I made one going north east and labeled it 5 degrees, and one going north west but i don't know what direction the arrowhead should go in...
 
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I'm not sure I understand what you're confused about in your solution. Could you attach an image of your drawing of the situation?

You could use the law of cos but I personally would do it in a simpler way.
 
Brian T said:
I'm not sure I understand what you're confused about in your solution. Could you attach an image of your drawing of the situation?
I cannot unfortunately, can you attach what you would think is the diagram for this?
 
hafsa786786786 said:
I cannot unfortunately, can you attach what you would think is the diagram for this?

You should be able to scan a sketch and upload it. Have you tried?
 
Moderator note: Please note that the thread title has been changed in order to make it more descriptive of the problem statement - gneill
 
berkeman said:
You should be able to scan a sketch and upload it. Have you tried?
berkeman said:
You should be able to scan a sketch and upload it. Have you tried?
 

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Well other than being sideways, that helps. The 2nd displacement should start at the end of the first displacement. So using arrows to represent the displacement vectors, keep the first one you've drawn from the origin with the arrow pointing up and right. Then put the start of the 2nd arrow at the upper tip of the first arrow, and draw it up and left. Basically you just have to redraw your 2nd displacement vector...
 

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