Relative motion -cheetah and gazelle

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SUMMARY

The problem involves calculating the time it takes for a cheetah running at 100 km/hr to catch a gazelle running at 80 km/hr, with the gazelle initially 70 meters ahead. The correct approach to solving this relative motion problem reveals that the cheetah closes the gap at a rate of 20 km/hr. Consequently, it takes 2.1 seconds for the cheetah to catch the gazelle, as it covers the 70 meters at the relative speed of 20 km/hr.

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  • Understanding of relative motion principles
  • Familiarity with speed conversion from km/hr to m/s
  • Basic algebra for solving equations
  • Knowledge of constant speed equations (s=vt)
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Kristin_Z
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Homework Statement


A cheetah can run at approximately 100km/hr and a gazelle at 80km/hr. If both animals are running at full speed, with the gazelle 70m ahead, how long before the cheetah catches its prey?

Homework Equations


s=vt (no acceleration)
v = km/hr / 3.6 = m/s

The Attempt at a Solution


I understand that this is relative motion. I've calculated that it takes the cheetah 2.52 s to run 70m and that during that 2.52 sec the gazelle would run an additional 55.9 m so that the total distance that the cheetah has to run is 125.9 meters. I've calculated that the time it takes for the cheetah to run this distance at constant speed is 4.53 s. I've redone this question about 10 times and can't figure out what I'm doing wrong. Can anyone please shed some light on what is probably a ridiculously easy question. Thank you.
 
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Kristin_Z said:

Homework Statement


A cheetah can run at approximately 100km/hr and a gazelle at 80km/hr. If both animals are running at full speed, with the gazelle 70m ahead, how long before the cheetah catches its prey?

Homework Equations


s=vt (no acceleration)
v = km/hr / 3.6 = m/s

The Attempt at a Solution


I understand that this is relative motion. I've calculated that it takes the cheetah 2.52 s to run 70m and that during that 2.52 sec the gazelle would run an additional 55.9 m so that the total distance that the cheetah has to run is 125.9 meters. I've calculated that the time it takes for the cheetah to run this distance at constant speed is 4.53 s. I've redone this question about 10 times and can't figure out what I'm doing wrong. Can anyone please shed some light on what is probably a ridiculously easy question. Thank you.

Make things simpler on yourself. Put yourself inside the head of the cheetah.

The cheetah sees dinner just 70 m away, and coming closer at the rate of 20 km/h.

Looked at another way, a student is waiting for a Pop Tart being delivered on a conveyor belt going at 20 km/h. The cafeteria worker is putting it on the conveyor from 70 m away. How long?

So how long does it take for that meal going at 20 km/h to travel 70m?
 
I've been looking at relative motion equations in 2d and having no problem but when I saw this one my brain was certain that somehow it had to be super complicated. Its not though. Thanks, is all makes sense now.
 

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