Relative Velocity of Object C to Object A = 10 m/s

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Homework Help Overview

The discussion revolves around the relative velocities of three objects, A, B, and C, with specific focus on determining the relative velocity of object C to object A given the relative velocities of B to A and C to B. The context involves vector equations and reference frames.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of vector equations to find the relative velocity, with some attempting to apply reference frames and others questioning the addition of velocities. There is confusion regarding the signs of the velocities and whether to add or subtract them.

Discussion Status

The discussion is ongoing, with participants providing different perspectives on how to approach the problem. Some guidance has been offered regarding the use of reference frames, but there is still confusion among participants about the correct method to apply.

Contextual Notes

Participants express uncertainty about the visualization of the problem and the implications of using negative velocities. There is mention of needing more information to clarify the setup of the problem.

nguyensteve
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Homework Statement


If the relative velocity of object B to object A is 10 m/s, and the relative velocity of object C to object B is 10 m/s, what is the relative velocity of object C to object A?

Homework Equations


These should be vectors just to give a heads up

vbs= vbw+vws

vba=vab

These are the equations given in my book

The Attempt at a Solution


My first attempt was using the second eqaution since the question before it was similar but it did not have c and I used the second formula and I got it right.
The second formula uses the idea of reference frames. So A and B have the same magnitude but different direction. So B and C is the same. So -10m/s -10m/s= -20 m/s. I was given this option and was told it was wrong. Then I made it an absolute value and it was wrong. So would it be -10m/s + 10m/s. Because if B is -10m/s, the opposite magnitude would be 10m/s and adding them together would give me 10? Or would I need more information to solve this.
 
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Convert B wrt A to A wrt B giving -10 then make point diagram of A B and C showing C 10 B 0 and A -10 meter per second this will give you the answer. Hope this helps.
 
So was I on the right track making one of them -10m/s and the other one 10m/s. So at this point do I add them to find the relative velocity of C to A. Making it 0 m/s? I find this part really confusing
 
No no you are not adding scalars, you are adding vectors afyer this step you have to go to A frame getting B = 10 and C = 20
 
For relative velocity wrt to A you always have to be in A's frame or can you use common sence. Always remember this point. Good question.

Cheers
 
I still don't understand this. I find it hard to visualize.
 
Then you need an offline physical world teacher to help you.
 
nguyensteve said:
vba=vab
Do you mean vba=-vab?
Daniel Dey said:
Convert B wrt A to A wrt B
Why do that? The first equation applies immediately.
 
Just ro help you visualise
 
  • #10
haruspex said:
Do you mean vba=-vab?

Why do that? The first equation applies immediately.
Yes
 

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