Relativistic energy/momentum conservation problem

  • Thread starter icedragon
  • Start date
  • #1
9
0

Homework Statement



A particle of rest mass m0 moving at a speed of 3/4 c collides with a same-mass particle at rest and they stick together to form a composite particle. What is the rest mass of the composite particle and what is its speed?

Homework Equations



[tex]E = \gamma mc^2[/tex]
[tex]p = \gamma mu[/tex]
[tex]\gamma = \frac{1}{\sqrt{1- \beta ^2}}[/tex]

The Attempt at a Solution



So far I have written out equations for initial energy and momentum and final energy and momentum. I rearranged both for [itex]\beta_{final}[/itex] and set them equal, with the aim of solving for [itex]v_{final}[/itex]. I got a velocity which was larger than the velocity of the initial particle which surely can't be right.

I won't write out all my workings as it would take an age but here is what I got for [itex]\beta_{final}[/itex] for the energy equation after cancelling/simplifying:

[tex]\beta_{final} = -3 -4 \beta_{initial} ^2[/tex]

And for the momentum equation:

[tex]\beta_{final} = 1 - \frac{(4 v_{final} ^2)(1 - \beta_{initial} ^2)}{v_{initial} ^2}[/tex]

As I said, I then set them equal and solved for [itex]v_{final}[/itex]. Any ideas?

Cheers!
 
Last edited:

Answers and Replies

  • #2
35,497
11,931
A small β_initial would lead to β_final close to -3. This cannot be right.
I don't see why you use both v and β, they just differ by a factor of c and it is convenient to use β everywhere. The second equation is wrong, too.

Do you know 4-vectors? It is possible to solve it without them, but this would be easier.
 
  • #3
Doc Al
Mentor
45,135
1,433
I won't write out all my workings as it would take an age but here is what I got for [itex]\beta_{final}[/itex] for the energy equation after cancelling/simplifying:

[tex]\beta_{final} = -3 -4 \beta_{initial} ^2[/tex]
Why don't we start with this one. How did you get this? What happened to the masses?
 
  • #4
9
0
A small β_initial would lead to β_final close to -3. This cannot be right.
I don't see why you use both v and β, they just differ by a factor of c and it is convenient to use β everywhere. The second equation is wrong, too.

Do you know 4-vectors? It is possible to solve it without them, but this would be easier.

Do you mean that the equation should be rest mass not mass? If so, the rest mass is given as [itex]m_0[/itex] but yeah I should have written it out fully. Nope I don't know 4-vectors. This is a coursework assignment and at this stage we haven't covered all the material so I am guessing I am supposed to solve using the methods we have covered.

Why don't we start with this one. How did you get this? What happened to the masses?

Using the first equation, for energy.

[tex]\frac{m_0 c^2}{\sqrt{1- \beta_{initial} ^2}} = \frac{2m_0 c^2}{\sqrt{1- \beta_{final} ^2}}[/tex]

Then I rearranged for [itex]\beta_{final} ^2[/itex]. [itex]m_0[/itex] and [itex]c[/itex] cancel out. Surely that is essential for solving as both final mass are unknowns?
 
Last edited:
  • #5
Doc Al
Mentor
45,135
1,433
Using the first equation, for energy.

[tex]\frac{m_0 c^2}{\sqrt{1- \beta_{initial} ^2}} = \frac{2m_0 c^2}{\sqrt{1- \beta_{final} ^2}}[/tex]

Then I rearranged for [itex]\beta_{final} ^2[/itex]. [itex]m_0[/itex] and [itex]c[/itex] cancel out. Surely that is essential for solving as both final mass are unknowns?
You have assumed that the rest mass of the composite particle is 2m0. Do not assume that! (That's one of the things you are trying to solve for.)

Edit: You also ignored the rest energy of one of the masses.
 
Last edited:
  • #6
vela
Staff Emeritus
Science Advisor
Homework Helper
Education Advisor
15,089
1,668
How did you come up with that equation? It makes no sense to me.

I suggest you stick with energies and momenta in your calculations. Write your equations in terms of E's and p's; don't write them in terms of velocities. It'll simplify the algebra quite a bit. Once you have the energy and momentum of the composite particle, then you can solve for its velocity.
 
  • #7
9
0
You have assumed that the rest mass of the composite particle is 2m0. Do not assume that! (That's one of the things you are trying to solve for.)

Edit: You also ignored the rest energy of one of the masses.

I had a feeling that was too simple to be true, thanks. I went through it again this time with [itex](m_0 + m_1)[/itex] instead of [itex]2m_0[/itex] and that gave me the final velocity equal to the initial velocity which can't be right? Am I missing something here?

EDIT: In the equation you quoted?
 
  • #8
Doc Al
Mentor
45,135
1,433
I had a feeling that was too simple to be true, thanks. I went through it again this time with [itex](m_0 + m_1)[/itex] instead of [itex]2m_0[/itex] and that gave me the final velocity equal to the initial velocity which can't be right? Am I missing something here?
I'm still not sure what you are doing. The rest mass of each particle before the collision is m0. Write the total energy of the system before the collision.

After the collision you have one combined particle. Call its mass m1. Write its total energy.

That's how you'd get your energy equation. Then do the same for momentum.
 
  • #9
9
0
I'm still not sure what you are doing. The rest mass of each particle before the collision is m0. Write the total energy of the system before the collision.

After the collision you have one combined particle. Call its mass m1. Write its total energy.

That's how you'd get your energy equation. Then do the same for momentum.

Ahh bugger me I completely forgot to include the energy of the stationary particle! Will have a go at it and report back.
 
  • #10
35,497
11,931
Do you mean that the equation should be rest mass not mass?
"Rest mass" and "mass" are the same.
The concept of a "relativistic mass" is not used in physics any more.
 
  • #11
9
0
"Rest mass" and "mass" are the same.
The concept of a "relativistic mass" is not used in physics any more.

I see, then what's wrong with the equation?

I've spent about 6 hours on this question now. I have tried to express the mass of the composite particle in terms of [itex]m_0[/itex] and then substitute into the energy equation but I just can't get a sensible answer out :/. And it's due in in 2 hours!
 
  • #12
Doc Al
Mentor
45,135
1,433
Please do as I asked in post #8 above. (Do not try to guess the mass of the composite particle. The equations will tell you that.)
 
  • #13
Doc Al
Mentor
45,135
1,433
Here's the idea:

Energy of particle 1 (mass = m0) + Energy of particle 2 (mass = m0) = Energy of composite particle (mass = m1)
 

Related Threads on Relativistic energy/momentum conservation problem

Replies
8
Views
691
Replies
1
Views
2K
Replies
3
Views
6K
  • Last Post
Replies
16
Views
3K
Replies
5
Views
1K
Replies
6
Views
1K
Replies
16
Views
430
Replies
1
Views
2K
Replies
6
Views
3K
Top