Relativistic energy/momentum conservation problem

Click For Summary

Homework Help Overview

The problem involves a collision between two particles of rest mass m0, where one particle is moving at a speed of 3/4 c and the other is at rest. The goal is to determine the rest mass and speed of the resulting composite particle after they collide and stick together.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of energy and momentum conservation equations, with some expressing confusion over the assumptions made regarding the rest mass of the composite particle. There are questions about the validity of the equations derived and the treatment of velocities versus beta values.

Discussion Status

There is ongoing exploration of the equations related to energy and momentum, with some participants suggesting a focus on these quantities rather than velocities. Multiple interpretations of the problem are being discussed, particularly regarding the treatment of rest mass and the assumptions made in the calculations.

Contextual Notes

Participants note that the problem is part of a coursework assignment, and some express uncertainty about the material covered, which may affect their approach to solving the problem. There is also mention of a deadline approaching, adding urgency to the discussion.

icedragon
Messages
9
Reaction score
0

Homework Statement



A particle of rest mass m0 moving at a speed of 3/4 c collides with a same-mass particle at rest and they stick together to form a composite particle. What is the rest mass of the composite particle and what is its speed?

Homework Equations



E = \gamma mc^2
p = \gamma mu
\gamma = \frac{1}{\sqrt{1- \beta ^2}}

The Attempt at a Solution



So far I have written out equations for initial energy and momentum and final energy and momentum. I rearranged both for \beta_{final} and set them equal, with the aim of solving for v_{final}. I got a velocity which was larger than the velocity of the initial particle which surely can't be right.

I won't write out all my workings as it would take an age but here is what I got for \beta_{final} for the energy equation after cancelling/simplifying:

\beta_{final} = -3 -4 \beta_{initial} ^2

And for the momentum equation:

\beta_{final} = 1 - \frac{(4 v_{final} ^2)(1 - \beta_{initial} ^2)}{v_{initial} ^2}

As I said, I then set them equal and solved for v_{final}. Any ideas?

Cheers!
 
Last edited:
Physics news on Phys.org
A small β_initial would lead to β_final close to -3. This cannot be right.
I don't see why you use both v and β, they just differ by a factor of c and it is convenient to use β everywhere. The second equation is wrong, too.

Do you know 4-vectors? It is possible to solve it without them, but this would be easier.
 
icedragon said:
I won't write out all my workings as it would take an age but here is what I got for \beta_{final} for the energy equation after cancelling/simplifying:

\beta_{final} = -3 -4 \beta_{initial} ^2
Why don't we start with this one. How did you get this? What happened to the masses?
 
mfb said:
A small β_initial would lead to β_final close to -3. This cannot be right.
I don't see why you use both v and β, they just differ by a factor of c and it is convenient to use β everywhere. The second equation is wrong, too.

Do you know 4-vectors? It is possible to solve it without them, but this would be easier.

Do you mean that the equation should be rest mass not mass? If so, the rest mass is given as m_0 but yeah I should have written it out fully. Nope I don't know 4-vectors. This is a coursework assignment and at this stage we haven't covered all the material so I am guessing I am supposed to solve using the methods we have covered.

Doc Al said:
Why don't we start with this one. How did you get this? What happened to the masses?

Using the first equation, for energy.

\frac{m_0 c^2}{\sqrt{1- \beta_{initial} ^2}} = \frac{2m_0 c^2}{\sqrt{1- \beta_{final} ^2}}

Then I rearranged for \beta_{final} ^2. m_0 and c cancel out. Surely that is essential for solving as both final mass are unknowns?
 
Last edited:
icedragon said:
Using the first equation, for energy.

\frac{m_0 c^2}{\sqrt{1- \beta_{initial} ^2}} = \frac{2m_0 c^2}{\sqrt{1- \beta_{final} ^2}}

Then I rearranged for \beta_{final} ^2. m_0 and c cancel out. Surely that is essential for solving as both final mass are unknowns?
You have assumed that the rest mass of the composite particle is 2m0. Do not assume that! (That's one of the things you are trying to solve for.)

Edit: You also ignored the rest energy of one of the masses.
 
Last edited:
How did you come up with that equation? It makes no sense to me.

I suggest you stick with energies and momenta in your calculations. Write your equations in terms of E's and p's; don't write them in terms of velocities. It'll simplify the algebra quite a bit. Once you have the energy and momentum of the composite particle, then you can solve for its velocity.
 
Doc Al said:
You have assumed that the rest mass of the composite particle is 2m0. Do not assume that! (That's one of the things you are trying to solve for.)

Edit: You also ignored the rest energy of one of the masses.

I had a feeling that was too simple to be true, thanks. I went through it again this time with (m_0 + m_1) instead of 2m_0 and that gave me the final velocity equal to the initial velocity which can't be right? Am I missing something here?

EDIT: In the equation you quoted?
 
icedragon said:
I had a feeling that was too simple to be true, thanks. I went through it again this time with (m_0 + m_1) instead of 2m_0 and that gave me the final velocity equal to the initial velocity which can't be right? Am I missing something here?
I'm still not sure what you are doing. The rest mass of each particle before the collision is m0. Write the total energy of the system before the collision.

After the collision you have one combined particle. Call its mass m1. Write its total energy.

That's how you'd get your energy equation. Then do the same for momentum.
 
Doc Al said:
I'm still not sure what you are doing. The rest mass of each particle before the collision is m0. Write the total energy of the system before the collision.

After the collision you have one combined particle. Call its mass m1. Write its total energy.

That's how you'd get your energy equation. Then do the same for momentum.

Ahh bugger me I completely forgot to include the energy of the stationary particle! Will have a go at it and report back.
 
  • #10
icedragon said:
Do you mean that the equation should be rest mass not mass?
"Rest mass" and "mass" are the same.
The concept of a "relativistic mass" is not used in physics any more.
 
  • #11
mfb said:
"Rest mass" and "mass" are the same.
The concept of a "relativistic mass" is not used in physics any more.

I see, then what's wrong with the equation?

I've spent about 6 hours on this question now. I have tried to express the mass of the composite particle in terms of m_0 and then substitute into the energy equation but I just can't get a sensible answer out :/. And it's due in in 2 hours!
 
  • #12
Please do as I asked in post #8 above. (Do not try to guess the mass of the composite particle. The equations will tell you that.)
 
  • #13
Here's the idea:

Energy of particle 1 (mass = m0) + Energy of particle 2 (mass = m0) = Energy of composite particle (mass = m1)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
6K
Replies
2
Views
2K
Replies
13
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K