 #1
Sconlan
 3
 0
 Homework Statement:

When the ship passes at velocity V1, the shuttle pilot measures the magnitude of the momentum of the spaceship to be p1.
On a subsequent mission, the spaceship again passes the shuttle, this time at twice the previous velocity, V2 = 2V1 = 0.840c.
The shuttle pilot again measures the momentum of the spaceship. In terms of p1, what is the magnitude of the measured momentum of the spaceship this time?
 Relevant Equations:

The relativistic momentum p of a material particle of mass m and velocity v is defined by the following vector equation:
p=mv/√(1v^2/c^2 )
The total relativistic energy of a particle m travelling at speed v is given by:
E_tot=(mc^2)/√(1v^2/c^2) = E_trans+E_mass.
Where:
E_trans = ((mc^2)/(1v^2/c^2))mc^2
And
E_mass = mc^2
The relationship between the total relativistic energy and the magnitude of the relativistic momentum can be expressed as:
(E_tot)^2 = p^2c^2+m^2c^4
I feel like this should be pretty straightforward knowing all the equations involved but my brain seems be stalling for some reason.