- #1

Sconlan

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- Homework Statement
- When the ship passes at velocity V1, the shuttle pilot measures the magnitude of the momentum of the spaceship to be p1.

On a subsequent mission, the spaceship again passes the shuttle, this time at twice the previous velocity, V2 = 2V1 = 0.840c.

The shuttle pilot again measures the momentum of the spaceship. In terms of p1, what is the magnitude of the measured momentum of the spaceship this time?

- Relevant Equations
- The relativistic momentum p of a material particle of mass m and velocity v is defined by the following vector equation:

p=mv/√(1-v^2/c^2 )

The total relativistic energy of a particle m travelling at speed v is given by:

E_tot=(mc^2)/√(1-v^2/c^2) = E_trans+E_mass.

Where:

E_trans = ((mc^2)/(1-v^2/c^2))-mc^2

And

E_mass = mc^2

The relationship between the total relativistic energy and the magnitude of the relativistic momentum can be expressed as:

(E_tot)^2 = p^2c^2+m^2c^4

I feel like this should be pretty straightforward knowing all the equations involved but my brain seems be stalling for some reason.