Resultant vector given initial velocity and acceleration

[idllotsaroms]

Homework Statement

http://postimage.org/image/466vu4yvp/
http://postimage.org/image/opdrmlv5n/

There can be more than one right answer

Homework Equations

α=Δv/ΔX
v = v0 + αt

The Attempt at a Solution

Im having difficulty understanding the upward acceleration vector. Because I set the +y direction as positive (up) and the +x-direction as positive (right). So I thought that if acceleration is up, it means that acceleration is positive so the velocity is increasing (just a vector that is the exact same as the Vo vector).
I attempted to add the two vectors together (hypotenuse) and say that was the answer, but it was incorrect (45° angle vector).

 

[tms]

You can't add an acceleration vector to a velocity vector; they have different units. And since you don't have any magnitudes and don't know how long the force acted, you are looking for a qualitative answer, not a quantitative one (that is, you couldn't have gotten a 45 degree angle). You are on the right track, though. Look at the possible answers and see if you can eliminate any of them.

 

[idllotsaroms]

thanks for the reply tms,
I guess my question then is, how am I supposed to add two unlike vectors?
So far, I eliminated A because I believe it doesn't make sense for there not to be a velocity vector.
C seems unlikely because of the initial velocity
E seems unlikely because that straight vector pointed right doesn't have the acceleration acting on it.
Would the answer be B and D, because they are the only resulting vectors that have the depicted upward acceleration acting on them with still pointing to the positive X-direction?

 

[tms]

thanks for the reply tms,
I guess my question then is, how am I supposed to add two unlike vectors?

You don't need exact results, just a general idea of what the effects of the force would be.

So far, I eliminated A because I believe it doesn't make sense for there not to be a velocity vector.

Right.

C seems unlikely because of the initial velocity

Right.

E seems unlikely because that straight vector pointed right doesn't have the acceleration acting on it.

Right.

Would the answer be B and D, because they are the only resulting vectors that have the depicted upward acceleration acting on them with still pointing to the positive X-direction?

Right.

 

[idllotsaroms]

... I swear I attempted that solution D:, but I tried it again and it worked! I think I accidentally submitted my response incorrectly!

Thank you tms for your help! (I was on my last attempt)