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- Homework Statement
- The movement of a material point of mass 500 mg is described using the following formula: ## v=9 \cdot \beta \cdot t^4 ## ,variable in time and is expressed in km/h. Considering the movement in the context of classical physics, and knowing the constant ## \beta=0.2 m \cdot s^{-5} ## . The resulting force which acts on the object at t=20s is equal to:

## 0.08 kg m \cdot s^{-5} ##

## 8 kg *m \cdot s^{-2} ##

80 N

8 kN

- Relevant Equations
- ## v=9* \beta * t^4 ##

## \beta = 0.2 m*s^{-5} ##

v(20)=288000 m/s=80000km/h

a=(80 000-0)/(20 -0)=4000 m*s^(-2)

F=m*a=0.0005*80 000 which doesn't fit any answers

a=(80 000-0)/(20 -0)=4000 m*s^(-2)

F=m*a=0.0005*80 000 which doesn't fit any answers

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