Reversible expansion according to a law pv^2 = constant

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The discussion focuses on a reversible expansion process governed by the law pv^2 = constant, involving a fluid initially at 0.7 bar and 0.009 m³, compressed to 3.5 bar. The fluid undergoes heating at constant volume until reaching 4 bar, with a specific volume of 0.5 m³/kg. Key calculations include the mass of the fluid at 0.0753 kg, the value of n in the compression process as 1.847, and the net work of the cycle calculated as -640 J.

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A fluid at 0.7bar occupying 0.009m3 is compressed reversibly to a pressure of 3.5bar according to a law pv^n = constant. The fluid is then heated reversibly at constant volume until the pressure is 4bar; the specific volume is then 0.5m3/kg . A reversible expansion according to a law pv^2 = constant restores the fluid to its initial state. Sketch the cycle on a p-v diagram and calculate:
I. The mass of fluid present
II. The value of n in the first process
III. The net work of the cycle
Answers:
0.0753kg; 1.847; -640
 
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need to solve this question before my exam period.
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