Reversible expansion according to a law pv^2 = constant

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megasima2006
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A fluid at 0.7bar occupying 0.009m3 is compressed reversibly to a pressure of 3.5bar according to a law pv^n = constant. The fluid is then heated reversibly at constant volume until the pressure is 4bar; the specific volume is then 0.5m3/kg . A reversible expansion according to a law pv^2 = constant restores the fluid to its initial state. Sketch the cycle on a p-v diagram and calculate:
I. The mass of fluid present
II. The value of n in the first process
III. The net work of the cycle
Answers:
0.0753kg; 1.847; -640
 
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need to solve this question before my exam period.
thanks for helping