A simple model of the core of a tornado is a right circular cylinder that rotates about its axis. If a tornado has a core diameter of 200 feet and maximum wind speed of 240 mi/hr (or 352 ft/sec) at the perimeter of the core, approximate the number of revolutions the core makes each minute. (Round your answer to one decimal place.)
s=r(theta) and V=r(omega)
The Attempt at a Solution
The practice problems had a radius and rpm given and I could find the angular and linear speeds, where I'm struggling is I'm not sure how to reverse the example in order to convert the speed and radius into rpm.
V=r(omega) then (omega)=V/r ???is that right? then when I plug the numbers:
omega=(352ft/sec)/(100ft/rad)....shoud I multipy the reciprocal being (1rad/100ft)
then get: omega=3.52rad/sec...
somewhere I'm sure pi has to come in, 2pi=1rpm...so do I multiply by 1/2pi ??? this is where I'm getting lost.