Rewrite function if moved by a vector and is mirrored

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SUMMARY

The discussion focuses on the transformations of the function f(x) when moved by a vector r=(a,b) and mirrored over the x or y axis. The correct transformations are established as follows: moving by the vector results in f(x) = f(x-a) + b, mirroring over the x-axis yields f(x) = -f(x), and mirroring over the y-axis gives f(x) = f(-x). For the specific function f(x) = x^2 + x - 4, the transformations are confirmed as f(x) = (x-a)^2 + (x - 4 + b) for the vector movement, f(x) = -x^2 - x + 4 for mirroring over the x-axis, and f(x) = -f(x) for mirroring over the y-axis.

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JG FRANKO
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1. There is a function f(x). Write regulations for it if: -you move it by a vector r=(a,b),
-you mirror it over x or y axis.2. f(x) isn't exactly given. Vector is r(a,b).3. If we move it by vector: f(x-a)+b,
If we mirror it over x: -f(x)
If we mirror it over y: f(-x)
So if I am correct, let's say we have f(x)=x^2+x-4, then when we move it for the vector: f(x)=x^(2-a)+x+(-4+b).
If we mirror it over x: f(x)=(-x)^2-x-4 and if we mirror it over y : f(x)=-(x^2)-x+4

Is this correct?

graphs of f(x) that I got for mirroring: https://www.wolframalpha.com/input/?i=f(x)=(-x)^2-x-4
https://www.wolframalpha.com/input/?i=f(x)=-(x^2)-x+4
 
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JG FRANKO said:
If we mirror it over x: f(x)=(-x)^2-x-4 and if we mirror it over y : f(x)=-(x^2)-x+4

I think the opposite mirror it over ##x##: ##f(x)=-(x^2)-x+4## and if we mirror it over ##y## : ##f(x)=(-x)^2-x-4##
 
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