In a right isosceles triangle with a hypotenuse of length 1, the lengths of the legs can be found using the Pythagorean theorem. Setting the length of each leg as "x," the equation becomes x² + x² = 1², simplifying to 2x² = 1. Solving for x gives x² = 1/2, leading to x = √(1/2). Rationalizing the denominator results in x = √2/2. Thus, the length of each leg in the triangle is √2/2.
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urekmazino
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For a right isosceles triangle (45-45-90) of hypotenuse 1, solve for the length of the unknown legs. Give an exact answer and rationalize the denominator in the final answer.
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I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...