Question: "A block of mass m1 = 1.87 kg and a block of mass m2 = 5.84 kg are connected by a massless string over a pulley in the shape of a solid disk having radius R = 0.180m and mass M = 12.7 kg. These blocks are allowed to move on a fixed block-wedge of angle 31.4 degrees as in the figure. The coefficient of kinetic friction is .357 for both blocks. A) Using free-body diagrams of both blocks and of the pulley, determine the acceleration of the two blocks. B) Determine the tensions in the string on both sides of the pulley. " Diagram BLOCK(m1) Pulley __________________\ \\ \\\\ \\\\\BLOCK (m2) \\\\\ ANGLE\\\\ _________________________\\ My basic question here is how I factor in the pulley. I'm assuming I need to incorporate torques with the pulley and convert them to forces such that I can find a F(net)=ma for each block. Block m1 WORK DONE: X: F(net) = T1(Tension of string) - F(friction) Y: F(net) = -m1g + N = 0 Block m2 WORK DONE: X: F(net) = m2gsin(Theta) - T2(String) - F(friction) Note: X is directed along the slope of the ramp. Y: F(net) = -m2gcos(Theta) + N = 0 Perpindicular to ramp. Thats as far as I got. Any help is appreciated.