Question: "A block of mass m1 = 1.87 kg and a block of mass m2 = 5.84 kg are connected by a massless string over a pulley in the shape of a solid disk having radius R = 0.180m and mass M = 12.7 kg. These blocks are allowed to move on a fixed block-wedge of angle 31.4 degrees as in the figure. The coefficient of kinetic friction is .357 for both blocks.(adsbygoogle = window.adsbygoogle || []).push({});

A) Using free-body diagrams of both blocks and of the pulley, determine the acceleration of the two blocks.

B) Determine the tensions in the string on both sides of the pulley.

"

Diagram

BLOCK(m1) Pulley

__________________\

\\

\\\\

\\\\\BLOCK (m2)

\\\\\

ANGLE\\\\

_________________________\\

My basic question here is how I factor in the pulley. I'm assuming I need to incorporate torques with the pulley and convert them to forces such that I can find a F(net)=ma for each block.

Block m1 WORK DONE:

X: F(net) = T1(Tension of string) - F(friction)

Y: F(net) = -m1g + N = 0

Block m2 WORK DONE:

X: F(net) = m2gsin(Theta) - T2(String) - F(friction)

Note: X is directed along the slope of the ramp.

Y: F(net) = -m2gcos(Theta) + N = 0

Perpindicular to ramp.

Thats as far as I got. Any help is appreciated.

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# Rigid Bodies and Free Body Diagrams (w pulley)

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