Robot starts to overturn when reaching to pick up a load

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The discussion centers on calculating the moment of a robot arm when it reaches to pick up a load, with specific equations provided for the moments of the robot, arm, and load. The calculations yield an incorrect distance of 1.09 feet instead of the expected 1.82 feet, prompting questions about the interpretation of the moment at point A and the significance of the "100" in the equation. Participants seek clarification on the terms used and the overall approach to solving the problem. The conversation highlights the complexity of moment calculations in robotics and the need for precise definitions in physics problems. Understanding these nuances is crucial for accurate problem-solving in engineering contexts.
crystallizedyogurt
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Homework Statement
The robot has an extendable arm that weighs 25 lb and picks up a 125-lb load at point B. If the robot starts to overturn when the moment at point A is 100 ft*lb, how far out (x) can the are extend
Relevant Equations
M = Force * Arm
IMG_1402.JPG



M robot = (125-25)lb* 1 ft = 25 lb*ft
M arm = 25 lb * (x/2 -1 )
M load = 125 lb * (x-1)
Mtotal =. 100 + 12.5 x -25 + 125 x -125 = 100
X = 1.09 ft
but the correct answer is 1.82 feet, why?
 
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crystallizedyogurt said:
Mtotal =. 100 + 12.5 x -25 + 125 x -125 = 100
What is the "100" on the left?
What, exactly, do you think is intended by "the moment at point A" in the question?
 
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