Robot starts to overturn when reaching to pick up a load

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SUMMARY

The discussion centers on the calculation of moments for a robot arm when picking up a load. The initial calculations yield a moment of 25 lb*ft for the robot and an equation for the total moment (Mtotal) that includes variables for the arm and load. The derived value of X is 1.09 feet, but the correct answer is established as 1.82 feet. Clarification is sought on the meaning of "100" in the equation and the interpretation of "the moment at point A."

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crystallizedyogurt
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Homework Statement
The robot has an extendable arm that weighs 25 lb and picks up a 125-lb load at point B. If the robot starts to overturn when the moment at point A is 100 ft*lb, how far out (x) can the are extend
Relevant Equations
M = Force * Arm
IMG_1402.JPG



M robot = (125-25)lb* 1 ft = 25 lb*ft
M arm = 25 lb * (x/2 -1 )
M load = 125 lb * (x-1)
Mtotal =. 100 + 12.5 x -25 + 125 x -125 = 100
X = 1.09 ft
but the correct answer is 1.82 feet, why?
 
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crystallizedyogurt said:
Mtotal =. 100 + 12.5 x -25 + 125 x -125 = 100
What is the "100" on the left?
What, exactly, do you think is intended by "the moment at point A" in the question?
 

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