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**Part 1 - Question About Torque Of Lever Arm in a 1st Class Lever**

**1. Homework Statement**

A little while back I posted a question about incorporating the torque of a uniform mass and dimension lever arm into the principle of a 1st class lever.

Here is the thread for reference.

https://www.physicsforums.com/showthread.php?t=340234"

I gave an answer that was deemed correct, but I am curious if I am supposed to incorporate the angle the lever is at as well?

Does the angle the lever is at (e.g. left side down low under a rock, right side high up in the air waiting for force to be applied) effect the calculation of torque in a first class lever?

**2. Homework Equations**

Does the angle the lever is at (e.g. left side down low under a rock, right side high up in the air waiting for force to be applied) effect the calculation of torque in a first class lever?

**3. The Attempt at a Solution**

I'm not familiar enough with physics to understand how to incorporate angles/"sin" into these equations.

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**Part 2 - Question About Torque Of Lever Arm in a 2nd Class Lever**

**1. Homework Statement**

How is the torque of a lever arm (uniform mass, uniform dimension) calculated and incorporated into the "equation/math" of a 2nd class lever?

I have a 12 foot, 200 lb. second class lever arm of uniform mass and dimension.

My fulcrum is attached to the ground, and underneath the lever at 2 feet from the fulcrum is a car that I am trying to smash. Basically, I have a nutcracker type second class lever that uses a lever arm and the ground.

**3. The Attempt at a Solution**

Is the Torque of this Lever Arm (6 foot x 200 lb.) 1200 foot lbs. which is added to the effort force when trying to generate enough "down force" at 2 feet to adequately crush the car?

Does the starting angle of the lever matter in calculating torque in this case?

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I appreciate any feedback.

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