Rockets burning in terms of momentum conservation

In summary: Can someone help me with this question please. I don't really understand what equations they are asking for and I don't have any work to show.
  • #1
lebbo
16
0
Can some one help me with this question please. don't really understand

mathematically analyse, using diagrams, rockets burning in terms of momentum conservation and the rate of fuel consumption R and derive the acceleration for a rocket during its launch stage.
 
Physics news on Phys.org
  • #2
Well, what do you know about the topic? What equations do you know? Show your work, and people will help you; however, we will not simply do your homework for you!
 
  • #3
lemme give u a tip...you need to remember that the mass is not constant and that the fuel used is continuously reducing the mass of the body...try to a get a start, use calculus and post how far you get...
 
  • #4
Be careful when you're looking for an explanation -- many high school/introductory undergraduate textbooks derive the rocket expressions with scalars, although they use vector tactics along the way. As I recall, Serway was one of the few that had a decent, correct explanation.

Also, the Internet is your friend. We're not going to just tell you how to do the problem, but nothing's stopping you from hunting down explanations online. That way, you'll learn by working through the derivations on your own.
 
  • #5
sry about that

we know that rockets momentum final= R

then the F= R/t

were R is the rate of fuel consumption and F is the total thrust

am i gettin there ?
 
  • #6
Well.. you might want to start by considering that momentum is always conserved.

If we imagine the rocket sitting in outer space it can make the thought process simpler.

If we assume initially the rocket is stationary its initial momentum will be zero, after it starts accelerating the total momentum of the system will still be zero (1st clue).

Secondly... Momentum = Mass * Velocity, however, in this case the mass of the rocket is not constant! Try working out the Thrust via differentiation.
 
  • #7
Why do you describe "R" as both the rate of fuel usage and the change of momentum?
 
  • #8
ok i think R=M/T

and therefore F=(R)(Vex)

Vex is the velocity when the rocket loses the fuel because it goes faster with less weight

total momentum intial= (M+m)V=0
total momentum final=M(V+v)=0
therefore total momentum: (M+m)V=M(V+v)

m : this is delta m is the fuel (before and after)
but wat do i do with the fuel that is expelled
 
  • #9
When you write F=R*Vex, if as you also say R=M/T

This is the thrust. However you then describe Vex as something other than the exhaust velocity (then it is not the thrust). Also, its very unclear what you mean by M and m.

Before you try solving this for the general case in which R might vary take R to be constant. Let's also assume that the exhaust velocity is constant.

I say this because your momentum equations look rather confused and we should sort that out first.

Vex = exhaust vel.
Mf = mass of Fuel.
M = Initial mass of rocket.
V = final mass of rocket

Once the rocket has used all its fuel...

Vex*Mf = (M-Mf)*V

Which is the bog standard cons. of mom. eqn.

If your ok with this then we can set up the "rocket equation".
 
Last edited:
  • #10
yea i get wat ur doing

ur sayin momentum before=momentum after
 
  • #11
I notice that you still haven't said exactly what the question is. That is important in deciding how to answer it!
 

What is momentum conservation?

Momentum conservation is a fundamental principle in physics that states that the total momentum of a system remains constant unless acted upon by external forces.

How does momentum conservation apply to rockets burning?

In a rocket, the burning of fuel produces a force that propels the rocket in the opposite direction. According to Newton's third law of motion, for every action there is an equal and opposite reaction. This means that as the rocket's fuel is expelled in one direction, the rocket is propelled in the opposite direction, conserving the total momentum of the system.

Why is momentum conservation important in rocket launches?

Momentum conservation is crucial in rocket launches because it ensures that the rocket will have enough thrust to overcome the force of gravity and escape Earth's atmosphere. If momentum conservation was not followed, the rocket would not be able to achieve enough velocity to reach space.

Does the mass of the rocket affect momentum conservation?

Yes, the mass of the rocket does affect momentum conservation. As the rocket's mass decreases due to burning fuel, its velocity increases in order to conserve momentum. This is why rockets are designed to be as lightweight as possible.

Are there any exceptions to momentum conservation in rocket launches?

There are no exceptions to momentum conservation in rocket launches. However, external forces such as air resistance and gravity can affect the rocket's momentum and must be taken into account during the design and launch process.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
219
  • Introductory Physics Homework Help
Replies
2
Views
187
  • Introductory Physics Homework Help
Replies
10
Views
654
  • Introductory Physics Homework Help
2
Replies
42
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
22
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
946
  • Introductory Physics Homework Help
Replies
2
Views
891
  • Introductory Physics Homework Help
Replies
15
Views
1K
Back
Top