Rock's Angular Motion in Bicycle Wheel Braking

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SUMMARY

The discussion focuses on the angular motion of a rock embedded in a 53.0 cm diameter bicycle wheel during braking. The rock's initial tangential speed is 3.50 m/s, and it experiences a tangential deceleration of 1.20 m/s². Key calculations include determining the rock's angular velocity (ω) and angular acceleration (α) at t = 1.60 seconds, with the correct formulas being applied. The discussion highlights the importance of using proper units, specifically radians for angular measurements, to ensure accurate results.

PREREQUISITES
  • Understanding of angular motion concepts
  • Familiarity with the equations of motion for rotational dynamics
  • Knowledge of unit conversions, particularly between linear and angular measurements
  • Basic proficiency in physics problem-solving techniques
NEXT STEPS
  • Study the relationship between linear velocity and angular velocity using the formula v = rω
  • Explore the concept of angular acceleration and its calculation using α = (ω_final - ω_initial) / t
  • Investigate the significance of significant figures in physics calculations
  • Learn about the effects of deceleration on angular motion in practical scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of angular motion and its applications in real-world scenarios, particularly in mechanics and engineering contexts.

freak_boy186
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Homework Statement


A rock stuck in the tread of a 53.0 cm diameter bicycle wheel has a tangential speed of 3.50 m/s. When the brakes are applied, the rock's tangential deceleration is 1.20 m/s^2.

X.) What is the magnitudes of the rock's angular velocity (omega) when t = 1.60s?
Y.) What is the magnitudes of the rock's angular acceleration (alpha) when t = 1.60s?
Z.) At what time is the magnitude of the rock's acceleration equal to g? (9.8 m/s^2)

Homework Equations


v = r(omega)
a = r(omega)^2
Vf = Vi + a[tangental](dt)
D[omega] = alpha(dt)
omega^2 = omega0^2 + 2(alpha)(dtheta)

The Attempt at a Solution


X.) r = 0.265m, a[tangental] = -1.2, Vi = 3.5, dt = 1.6
Vf = 3.5 + (-1.2)(1.6) = 1.58
omega = 1.58/0.265 = 5.962 {incorrect apparently}

Y.) omega1 = 3.5/.265 = 13.208
(13.208 - 5.962) = alpha(1.6)
alpha = 4.528 {incorrect, but expected because X is incorrect}
 
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freak_boy186 said:

Homework Statement


A rock stuck in the tread of a 53.0 cm diameter bicycle wheel has a tangential speed of 3.50 m/s. When the brakes are applied, the rock's tangential deceleration is 1.20 m/s^2.

X.) What is the magnitudes of the rock's angular velocity (omega) when t = 1.60s?
Y.) What is the magnitudes of the rock's angular acceleration (alpha) when t = 1.60s?
Z.) At what time is the magnitude of the rock's acceleration equal to g? (9.8 m/s^2)

Homework Equations


v = r(omega)
a = r(omega)^2
Vf = Vi + a[tangental](dt)
D[omega] = alpha(dt)
omega^2 = omega0^2 + 2(alpha)(dtheta)

The Attempt at a Solution


X.) r = 0.265m, a[tangental] = -1.2, Vi = 3.5, dt = 1.6
Vf = 3.5 + (-1.2)(1.6) = 1.58
omega = 1.58/0.265 = 5.962 {incorrect apparently}
That's correct. Maybe you're not entering it in the right units or with the correct number of significant figures.
Y.) omega1 = 3.5/.265 = 13.208
(13.208 - 5.962) = alpha(1.6)
alpha = 4.528 {incorrect, but expected because X is incorrect}
That's correct too, although you took a roundabout way of calculating it.
 
its asking for omega in rad/sec & alpha in rad/sec^2... would that affect my answers any?
 
Nope. Radians is the natural unit for measuring angles.
 

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