Calculating Roller Coaster Speed at Top of Loop-the-Loop

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SUMMARY

The discussion focuses on calculating the speed of a roller coaster car at the top of a loop-the-loop with a diameter of 37 meters. The key equation used is the normal force equation, where the normal force equals the gravitational force (n - mg = 0). Participants emphasize the need to identify the centripetal force acting radially inward on the car to solve for its speed. The solution requires understanding the relationship between gravitational force and centripetal acceleration.

PREREQUISITES
  • Understanding of centripetal force in circular motion
  • Knowledge of gravitational force and its calculation
  • Familiarity with Newton's second law of motion
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of centripetal acceleration and its formula
  • Learn how to derive the gravitational force acting on an object
  • Explore applications of Newton's laws in circular motion
  • Practice solving problems involving forces in circular paths
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of roller coasters and circular motion in mechanics.

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Homework Statement


The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 37 m diameter loop-the-loop.
What is the car's speed at the top?

Homework Equations


n-mg=0
I don't know what equation to use

The Attempt at a Solution


I honestly don't know what to do...
 
Physics news on Phys.org
You have to do something. What's the force called which acts radially inward on a mass going in a circle? And what's the magnitude?
 

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