Roots of an irreducible polynomial over a finite field

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SUMMARY

The discussion focuses on the irreducible polynomial f(x) = x^3 + x + 1 over the finite field F = Z2. It establishes that if a is a root of f(x), then both a^2 and a^2 + a are also roots of the polynomial. The proof utilizes the properties of fields of characteristic 2, specifically that a^3 = a + 1, to compute f(a^2) and demonstrate that it equals zero. The same method can be applied to show that a^2 + a is also a root of f(x).

PREREQUISITES
  • Understanding of finite fields, specifically Z2.
  • Knowledge of polynomial functions and their roots.
  • Familiarity with field extensions and their properties.
  • Basic concepts of algebra in characteristic 2.
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  • Explore the structure of finite fields and their extensions.
  • Study the properties of irreducible polynomials over finite fields.
  • Learn about the application of field theory in coding theory.
  • Investigate the computational methods for finding roots of polynomials in finite fields.
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Mathematicians, computer scientists, and cryptographers interested in algebraic structures, polynomial equations, and their applications in coding theory and cryptography.

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Let F=Z2 and let f(x) = X^3 +x+1 belong to F[x]. Suppose that a is a zero of f(x) in some extension of F.
Using the field created above F(a)
Show that a^2 and a^2+a are zeros of x^3+x+1?
 
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If $a$ is a root of $x^3 + x + 1 \in \Bbb Z_2[x]$, it follows that in $\Bbb Z_2(a)$, we have:

$a^3 = a + 1$ (recall that in any field of characteristic $2$, we have $b = -b$, for any element $b$).

It is straightforward to compute $f(a^2)$:

$f(a^2) = (a^2)^3 + (a^2) + 1 = (a^3)^2 + a^2 + 1 = (a+1)^2 + a^2 + 1$

$= a^2 + (a+a) + 1 + a^2 + 1 = a^2 + 0 + 1 + a^2 + 1 = (a^2 + a^2) + (1 + 1)$

$= a^2(1 + 1) + (1 + 1) = (a^2 + 1)(1 + 1) = (a^2 + 1)(0) = 0$.

This shows $a^2$ is likewise a root of $f$, since $f(a^2) = 0$.

Now can you do the same with $a^2 + a$?
 

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