M. next said:
Thanks for your reply, but I was pointing to a different road, my question in other words is how to derive, rotation operator for spin 1? How do we get there?
How did you find the rotation operator for spin 1/2? You probably started with the rules for the generators [itex]J_i[/itex], namely the commutation relation
[tex][J_i,J_j] = i \epsilon_{ijk} J_k[/tex]
and the eigenvalue conditions
[tex]J^2 | j,m\rangle = j(j+1) | j,m\rangle,~~~J_3 | j,m\rangle = m | j,m\rangle .[/tex]
You then have to choose a set of basis vectors to correspond to the states [itex]| j,m\rangle[/itex]. You can choose a basis so that [itex]J_3[/itex] is diagonal. From here, you can use trial and error to find a pair of matrices that have the correct commutation relations with [itex]J_3[/itex] and satisfy the [itex]J^2[/itex] equation. Otherwise you can form the raising and lowering operators
[tex]J_\pm = \frac{1}{\sqrt{2}} (J_1\pm iJ_2),[/tex]
[tex]J_3 J_\pm | j,m\rangle = (m\pm 1) | j,m\pm 1\rangle[/tex]
and note that
[tex]J_+ | 1,1\rangle = J_- | 1,-1\rangle =0.[/tex]
These last conditions can be solved with less guesswork.
Once you have the generators, you can exponentiate them to find the rotation matrices.