Rotational Kinematics (Ball hits stick)

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SUMMARY

The discussion centers on a physics problem involving a 1 kg ball traveling at 10 m/s colliding with a 1 kg stick of length 1.2 m and rotational inertia calculated as 1/12 ML². After the collision, the stick rotates upward by 90 degrees, and the ball's velocity decreases to 6.57 m/s. The kinetic energy lost during the collision is determined to be 5.88 J, leading to a new velocity of the ball at 3.43 m/s. The main challenge highlighted is calculating the angle theta, which represents the change in direction of the ball post-collision.

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Homework Statement


A 1 kg ball is traveling horizontally at 10 m/s. It hits a stick of mass 1kg and length 1.2m (rotational inertia 1/12 M L^2) at the bottom of the stick, which rotates upward 90 degrees from its previous location. The ball's direction changes by an angle theta. Find theta and the new velocity.



Homework Equations


U potential=mgh
K=(1/2)mv^2
L=Iw
K=(1/2)Iw^2


The Attempt at a Solution


U of stick=(1)(9.8)(.6)=5.88
This equals Kinetic Energy lost
5.88=(1/2)(1)(v^2)
v=3.43
10-3.43=6.57m/s

I have no idea how to find the theta though. I don't understand why the ball would even change direction. Wouldn't it just go the same direction at a slower pace?
 
Last edited:
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I'm not sure this problem is possible, without at least knowing where on the stick the ball hit and how fast the stick was moving...
 
Sorry about that.

I made the edit to include that it hits the stick at the bottom.
 

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