Rotational Mechanics: Plank Acceleration and Frictional Force Calculation

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SUMMARY

The discussion focuses on calculating the linear acceleration of a plank and the frictional force acting on it, given a constant horizontal force of 6 N. The plank has a mass of 3.7 kg and rides on two solid cylindrical rollers, each with a mass of 2.9 kg and a radius of 5.5 cm. The equations of motion utilized include τ=Fr, Ʃτ=Iα, and F=ma. The solution requires applying these equations to derive both the acceleration of the plank and the frictional force acting on it.

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Homework Statement



A plank having mass 3.7 kg rides on top of two identical solid cylindrical rollers each having radius 5.5 cm and mass 2.9 kg. The plank is pulled by a constant horizontal force of 6 N applied to its end and perpendicular to the axes of the cylinders(which are parallel). The cylinders roll without slipping on a flat surface. There is also no slipping between the cylinders and the plank.

1.) Find the acceleration(linear) of the plank(m/s^2).

2.) Find the frictional force acting acting on the plank(N).

M=3.7 kg
m=2.9 kg
r=.055 m
F=6 N
α = angular acceleration
a=linear acceleration


Homework Equations



τ=Fr
Ʃτ=Iα
F=ma
Frictional force(static) = force applied

The Attempt at a Solution


 
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