How Do You Calculate Angular Acceleration from RPM?

Click For Summary
To calculate angular acceleration from RPM, the initial and final RPM values must be converted to radians per second using the formula 1 RPM = (2π/60) rad/s. For a wheel with a diameter of 61 cm accelerating from 120 RPM to 280 RPM over 4 seconds, the correct conversions yield approximately 12.57 rad/s and 29.32 rad/s, respectively. The angular acceleration is then calculated by taking the change in angular velocity and dividing it by the time interval, resulting in an angular acceleration of about 4.2 rad/s². The initial calculations presented were incorrect due to an error in the RPM to rad/s conversion. Accurate conversions are crucial for obtaining the correct angular acceleration value.
J-Fly
Messages
5
Reaction score
0
Warning! Formatting template must be used in the homework sections!
A 61 cm diameter wheel accelerated uniformly about its center from 120 rpm to 280 rpm in 4.0 seconds. Determine the Angular acceleration

So I converted the 120 and 280 rev per min to radians per s with 45238.93 rad/s and 105557.51 rad/s and used them as angular velocity final and initial. then I subtracted the final from the initial and divided it by the time (4 sec)

Equation used angular acceleration (fish) = change in angular velocity/time

Answer gotten: 15 x 103 rad/s2 with sig figs.

on the answer sheet= 4.2 rad/s2
 
Physics news on Phys.org
Can you show your calculations for converting the given rpm values to radians per second? Your values look rather high.
 
er
J-Fly said:
A 61 cm diameter wheel accelerated uniformly about its center from 120 rpm to 280 rpm in 4.0 seconds. Determine the Angular acceleration

So I converted the 120 and 280 rev per min to radians per s with 45238.93 rad/s and 105557.51 rad/s and used them as angular velocity final and initial. then I subtracted the final from the initial and divided it by the time (4 sec)

Equation used angular acceleration (fish) = change in angular velocity/time

Answer gotten: 15 x 103 rad/s2 with sig figs.

on the answer sheet= 4.2 rad/s2
There is a problem with your conversion. Note that 1rpm=(2pi*1)/60 rad/s
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
Replies
2
Views
2K
Replies
1
Views
2K