S matrix and decaying particles

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SUMMARY

The S-matrix is defined as the inner product of in- and out-states, specifically represented as S_{βα}=(Ψ−β,Ψ+α) in Weinberg's QFT volume 1. The discussion highlights the complexities of incorporating unstable particles like neutrons into the S-matrix formalism, particularly regarding their decay rates and the treatment of neutrinos. It is established that while neutrons are not eigenstates of the full Hamiltonian, their decay can still be computed using the S-matrix by treating them as resonances in scattering processes. The decay rate is linked to the imaginary part of the pole location in the scattering amplitude, and the PMNS matrix plays a crucial role in understanding neutrino oscillations.

PREREQUISITES
  • Understanding of S-matrix formalism in quantum field theory
  • Familiarity with Weinberg's QFT volume 1
  • Knowledge of the PMNS matrix and neutrino oscillations
  • Concepts of eigenstates and decay rates in quantum mechanics
NEXT STEPS
  • Study the optical theorem as discussed in Peskin-Schröder, chapter 7
  • Learn about the implications of the PMNS matrix on neutrino decay rates
  • Explore Srednicki's text for additional insights on unstable particles
  • Research the relationship between scattering amplitudes and decay rates in quantum field theory
USEFUL FOR

Physicists, particularly those specializing in quantum field theory, particle physics researchers, and students exploring the behavior of unstable particles and neutrinos.

pscplaton
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Hi All,

The S-matrix is defined as the inner product of the in- and out-states, as in Eq. (3.2.1) in Weinberg's QFT vol 1:
S_{βα}=(Ψ−β,Ψ+α)

\Psi_{±α} are the eigenstates of the full Hamiltonian with a non-zero interaction term.

Can \alpha describes a neutron ? Since it is not stable, it is not an eigenstate of the full Hamiltonian, so it should not... But then how can you compute the decay rate of the neutron within the S matrix formalism ?

I am also wondering how to take neutrinon into account. Supposing \alpha can describe a neutron,
the neutron may decays as: n → p + e^− + \overline{\nu}_e. But \overline{\nu}_e is not an eigenstate of the full Hamiltonian ; I would rather use the mass eigenstates \nu_1, \nu_2, \nu_3. But then it means that the S matrix formalism is unable to predict that it is really a \nu_e that is created at the time of the interaction, which could lead to false predictions... What do you think ?
 
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If you have access to Peskin-Schröder, there is a discussion on unstable particles in chapter 7 in relation to the discussion of the optical theorem.

When it regards neutrinos, you are right. The states should really be the mass eigenstates. However, they remain coherent over pretty large distances due to the very small mass splittings, resulting in neutrino oscillations. If you do not measure the neutrino, you can simply do the total decay rate as a sum of the decay rates into the different mass eigenstates. The result will be essentially ##\Gamma = (|U_{e1}|^2+|U_{e2}|^2+|U_{e3}|^2)\Gamma_0##, where ##\Gamma_0## is the decay rate you would have to one neutrino state if there was no mixing and ##U## is the PMNS matrix. Since the PMNS (as far as we know) is unitary, the sum of the squared PMNS matrix elements equals 1.
 
Strictly speaking, only stable particles are allowed in the in and out states. The neutron then appears as a resonance in scattering of a neutrino, electron, and proton. The decay rate is identified with the imaginary part of the location of the pole in the scattering amplitude.

Happily, it turns out that this decay rate is equivalent to what you get by starting with a neutron in the in state, even though you are not really allowed to do this.

Srednicki's text also has a discussion of this.
 
Thanks for your replies. I will have a look to these references
 

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