^.^'s question at Yahoo Answers (Linearization)

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The linearization L(x) of the function f(x) = ln(4x) at x = 1/4 is determined to be L(1/4)(h) = 4h. The derivative f'(x) is calculated as f'(x) = 1/x, leading to f'(1/4) = 4. This linear approximation is expressed in classical notation as L(1/4)(dx) = 4 dx, providing a clear method for estimating the function's behavior near the point of interest.

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Hello ^.^,

Deriving: $f'(x)=\dfrac{4}{4x}=\dfrac{1}{x}$, so $f'(1/4)=\dfrac{1}{1/4}=4$. Now by definition of $L$, $$L(1/4):\mathbb{R}\to \mathbb{R}\\L(1/4)(h)=f'(1/4)h=4h$$ Or in classical notation, $L(1/4)\;(dx)=4\;dx$.

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