MHB ^.^'s question at Yahoo Answers (Linearization)

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The linearization L(x) of the function f(x) = ln(4x) at x = 1/4 is derived by first calculating the derivative, which is f'(x) = 1/x. Evaluating this at x = 1/4 gives f'(1/4) = 4. The linearization is expressed as L(1/4)(h) = 4h, or in classical notation, L(1/4)(dx) = 4 dx. For additional questions, users are encouraged to visit a specified math help forum.
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Hello ^.^,

Deriving: $f'(x)=\dfrac{4}{4x}=\dfrac{1}{x}$, so $f'(1/4)=\dfrac{1}{1/4}=4$. Now by definition of $L$, $$L(1/4):\mathbb{R}\to \mathbb{R}\\L(1/4)(h)=f'(1/4)h=4h$$ Or in classical notation, $L(1/4)\;(dx)=4\;dx$.

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