MHB Sammy's question at Yahoo Answers (Laurent expansion)

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The discussion focuses on finding the Laurent series for the function cos(z)/z centered at z=0. The Maclaurin series for cos(z) is provided, which is the basis for deriving the Laurent series. The resulting Laurent series for cos(z)/z is expressed as a sum that includes a term 1/z and an infinite series. Participants are encouraged to ask further questions in a designated math help forum. This response aims to clarify the mathematical concept for the original poster.
Fernando Revilla
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Hello Sammy,

The Maclaurin expansion of $\cos z$ is: $$\cos z=\sum_{n=0}^{\infty}\frac{(-1)^nx^{2n}}{(2n)!}\qquad (\forall z\in\mathbb{C})$$ so, the Laurent series expansion for $\cos z/z$ centered at $z=0$ is $$\frac{\cos z}{z}=\sum_{n=0}^{\infty}\frac{(-1)^nx^{2n-1}}{(2n)!}=\frac{1}{z}+\sum_{n=1}^{\infty}\frac{(-1)^nx^{2n-1}}{(2n)!}\quad (0<|z|<+\infty)$$ If you have further questions, you can post them in the http://www.mathhelpboards.com/f50/ section.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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