roshan2004
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In what conditions do we use time dependent and time independent Schrödinger's wave equations?
The discussion centers on the appropriate use of the time-dependent Schrödinger equation (TDSE) versus the time-independent Schrödinger equation (TISE). The TISE is specifically applicable for stationary states and time-independent potentials, while the TDSE is preferred for time-dependent potentials. Participants emphasize that the choice of equation depends on the nature of the potential, with the TISE being more suitable for analyzing energy eigenvalues and eigenstates when the potential is not time-dependent. The conversation also highlights the importance of understanding that both equations describe the same physics, with the TDSE being a more general form.
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Gerenuk said:The time-dependent version is always the right choice.
However if your potential does not depend on time, but position only V(x) (unlike V(x,t)), then you can use the trial solution \psi(x,t)=\phi(x)e^{-i E t/\hbar} and derive an equation for the special part \phi of the wavefunction. You effectively get the time-independent version of the Schrödinger equation. From this time-indepedent special case you can first find \phi and E and finally put it back into the full wavefunction \psi(x,t). Please try that above exercise with the trial solution.
<br /> <br /> Read my first sentence again .. you said it is *always* best to use the TDSE. I said it is best to use the TISE when solving a time independent potential. <br /> <br /> To answer your question, yes, I would also tend to use the TISE first in cases where it is appropriate to treat the time-variant part of the potential as a (weak) perturbation.<br /> <br /> In cases where there is truly a strongly-coupled time-dependent potential to deal with, I would probably not use either form of the Schrödinger equation, but instead I would formulate solutions in the interaction picture, where quantum propagators are used to describe the time-evolution of some initial state, which I would represent as a linear combination of eigenstates. Of course that choice is largely due to my own education and training, and the sorts of problems I run into in my research. Honestly, outside of fairly straightforward derivations and pedagogic illustrations, I have found little use for the TDSE.<br /> <br /> I understand that others will have a different take .. I was just providing a counter-example to your statement that, "The time-dependent version is always the right choice."Gerenuk said:It's not a matter of taste. What you want to use merely depends on whether your potential is V(x,t) or V(x)[/tex]. What time-independent eigenstates do you want to find if you haven't even given a time-independent potential to deal with?<br /> <br /> Maybe you are referring to some perturbation theory approximations?
I wanted to emphasize that there is only one equation that describes the physics. Everything else is a special case. This is to prevent misconceptions about "dualities" and "special cases".SpectraCat said:I understand that others will have a different take .. I was just providing a counter-example to your statement that, "The time-dependent version is always the right choice."
roshan2004 said:In what conditions do we use time dependent and time independent Schrödinger's wave equations?