Schwinger-Dyson equations derivation

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    Derivation
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Discussion Overview

The discussion revolves around the derivation of the Schwinger-Dyson equations, specifically focusing on the appearance of the commutator in the derivation process. Participants explore the implications of delta functions and Heaviside functions within this context.

Discussion Character

  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant expresses confusion about obtaining the commutator in the derivation, questioning the absence of a minus sign and suggesting that an anticommutator would be more appropriate.
  • Another participant suggests rewriting ##\theta (-t)## in terms of ##\theta (t)## and recommends drawing a graph to aid understanding.
  • A third participant proposes using the chain rule for differentiation as a potential approach to clarify the issue.
  • A later reply indicates that one participant believes they have resolved their confusion but does not specify how.

Areas of Agreement / Disagreement

The discussion reflects a lack of consensus, with participants presenting differing viewpoints and approaches to understanding the derivation without resolving the initial confusion about the commutator.

simonjech
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This is the part of Schwinger-Dyson equations derivation. I did not understand how can we obtain the commutator in the last line of the picture. I understand why the delta functions appeared from Heaviside functions but there is no minus sign in any term so how can we get the commutator? Anticommutator would make more sence for me.
Screenshot_20230305_212957_Drive.jpg
 
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Write down ##\theta (-t)## in terms of ##\theta (t)##. Drawing the graph of ##\theta (-t)## helps.
 
Last edited:
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Or just use the chain rule for differentiation
 
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I think that i figured it out. The problem was that I did not realized that
Screenshot_20230306_154107_Math Editor.jpg
.
 
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