Second Solution to Bessel's Function of order zero

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SUMMARY

The discussion centers on the Frobenius Method for solving Bessel's function of order zero in the exceptional case where r1 equals r2. Two formulations for the second solution are presented: y2 = y1 ln(x) + x^(r1+1)∑(n=0 to ∞) b_n x^n and y2 = y1 ln(x) + x^(r1)∑(n=1 to ∞) b_n x^n. Both formulations yield the same result, with the primary difference being the starting index of the summation (n=0 vs. n=1). The user ultimately resolves their query independently.

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cybla
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Frobenius Method Exceptional case r1=r2

For the Frobenius Method for the exceptional case r1=r2... is the equation for the second solution


y_{2}= y_{1} ln (x) + x^{r_{1}+1}\sum_{n=0}^{\infty}b_{n}x^{n}

or

y_{2}= y_{1} ln (x) + x^{r_{1}}\sum_{n=1}^{\infty}b_{n}x^{n}

In a way both of them give the same exact answer however one begins with b_{0}x (the first one that begins at n=0) ...and the other begins with b_{1}x (the second one that begins at n=1)

Does it matter which one i use? Is one simpler than the other?
 
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