Seemingly easy problem having to do with current?

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SUMMARY

The problem involves calculating the current during a lightning strike where 2.5 coulombs (C) of charge flows to the ground in 0.020 milliseconds (ms). The correct calculation for current is achieved using the formula I = Q/t, where I is current, Q is charge, and t is time. The user initially miscalculated the time as 0.0002 seconds instead of the correct 0.00002 seconds. The accurate current during the lightning strike is 125,000 amperes (A).

PREREQUISITES
  • Understanding of electric current and charge (I = Q/t)
  • Basic knowledge of time measurement in seconds and milliseconds
  • Familiarity with units of measurement in physics (coulombs, amperes)
  • Ability to perform unit conversions accurately
NEXT STEPS
  • Review the concept of electric current and its calculation methods
  • Study the significance of time units in physics, particularly milliseconds
  • Learn about the implications of high current in electrical phenomena
  • Explore real-world applications of current calculations in electrical engineering
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Students in physics, electrical engineering learners, and anyone interested in understanding the principles of electric current and its calculations during transient events like lightning strikes.

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Homework Statement



In a typical lightning strike, 2.5 C flows from cloud to ground in .020 ms. What is the current during the strike?

Homework Equations



I've been doing 2.5 C / .0002 s = 12,500. However, this is not right.

The Attempt at a Solution



Am I using the wrong formua? This problem seems so easy I don't know where I'm messing up.
 
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Hello csimon current =charge/time so it seems you are using the correct formula.The time is 0.02ms=0.00002s not 0.0002ms
 

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