Selecting the proper motor to spin a brush

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SUMMARY

The discussion focuses on selecting an appropriate motor for spinning a 12-inch brush designed for window cleaning, which experiences a horizontal force of 5 pounds and operates at 200 RPM. The user is evaluating a DC motor from Pololu (product ID 1104) and seeks to calculate the necessary torque, factoring in rotational inertia and angular acceleration. The conversation emphasizes the importance of using the speed-torque curve of the motor, which indicates a free-run speed of 200 RPM and a stall torque of 170 oz-in, to determine the motor's performance characteristics.

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Hello I need to select the proper motor to spin a 12 inch brush that cleans a window. There is about 5 pound of horizontal force on the window and the brush will spin at 200 rpm . My issue in finding what torque needs to be supplied by the motor. When a DC motor is turned on it almost immediately achieves the velocity corresponding to a certain voltage. How can I determine this acceleration. I selected a motor that I feel would be more than enough http://www.pololu.com/catalog/product/1104" but I need to show calculations for my project. Maybe I will use a controller to slowly increase the speed and then assume no angular acceleration. Any help would be greatly appreciated.
 
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torque = rotational inertia * angular acceleration.

With some maths, perhaps calculus, and the speed-torque curve of the motor (200 RPM free-run, 170 oz-in stall.), you can predict the time taken to reach 190RPM, or something else close enough.
 

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